1樓：匿名使用者
用標準sql的with實現遞迴查詢（sql2005以上肯定支援，sql2000不清楚是否支援）：
with subqry(id,name,pid) as (select id,name,pid from test1 where id = 5
union all
select test1.id,test1.name,test1.pid from test1,subqry
where test1.pid = subqry.id)select * from subqry;
2樓：匿名使用者
select * from tablename where pid=@pid
3樓：
1 set ansi_nulls on
2 go
3 set quoted_identifier on
4 go
5 6 create function [dbo].[fn_getsubcasnotree](@cas_no varchar(20))
7 returns @cas table
8 (9 cas_no varchar(20) collate database_default,這個不加sql2000會報錯。
10 level int
11 )
1213 as
14 begin
15 declare @level int
16 set @level = 1
17 insert into @cas select @cas_no , @level
18 while @@rowcount > 0
19 begin
20 set @level = @level + 1
21 insert into @cas select a.cas_no , @level
22 from casn a , @cas b
23 where a.up = b.cas_no and b.level = @level - 1
24 end
25 return
26 end
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